![]() Learn how to install a bleed down resistor on your start cap. The important part is if your original capacitor had one, you'll need to replace it on the new capacitor. Not all start capacitors will use one, as there are other ways to accomplish this. The purpose of the resistor is to bleed off residual voltage in the capacitor after it has been disconnected from the circuit after motor start up. The resistors are usually either soldered or crimped to the terminals. This should read somewhere around 10-20k Ohms and around 2 watts. You can check the condition of the old one by checking the resistance value, or just replace it with a new one. Most replacement start capacitors will not include a resistor. Watch the video tutorial below to learn the differences between start and run capacitors. A startcapacitor can not ever be used as a run capacitor, because it could not handle current continuously (only a couple of seconds). The capacitance and voltage ratings would have to match the original start capacitor specification. In unusual circumstances, a run capacitor could be used as a start capacitor, but the values available are much lower than the values usually available for dedicated start capacitors. They are generally of a much lower capacitance value.Īre start and run capacitors interchangeable? ![]() Run capacitors are used for continuous voltage and current control to a motor's windings and are therefore continuous duty. They are only intermittent duty and will fail catastrophically if energized too long. Start capacitors give a large capacitance value necessary for motor starting for a very short (seconds long) period of time. Because of this, start capacitors will fail after being left energized for too long due to a faulty starting circuit on a motor. As a result, they are only intended for intermittent duty. Start capacitors possess a very large capacitance value for their size and voltage rating. A start capacitor is used to briefly shift phase on a start winding in a single phase electric motor to create an increase in torque.
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